What is the area (in m2) of a triangular field whose sides measure 25 m, 39 m and 56 m?
Answer & explanation
Correct answer: option 3
The three sides of a triangle are = 25 m, 39 m and 56 .
Let the sides of triangle = a, b and c
Semi perimeter = \(\frac{a + b + c}{2}\)
Semi perimeter= \(\frac{25 + 39 + 56}{2}\) = 60
Area of a triangle = \(\sqrt {s(s-a)(s-b)(s-c) }\)
= \(\sqrt {60(60-25)(60-39)(60-56) }\)
= \(\sqrt {60(35)(21)(4) }\)
= \(\sqrt {176400}\) = 420