Identify the correct statement(s):

1. Fluorine is a stronger oxidizing agent than chlorine.

2. Sulphur in vapour state shows paramagnetic behaviour

3. $H_2S$ is more acidic than $H_2Te$

4. Fluorine form two oxoacids $HOF$, $HOFO$

Choose the correct answers from the options given below:

A and B only

The correct answer is option 1. A and B only

Let us analyze each statement:

A. Fluorine is a stronger oxidizing agent than chlorine.

This statement is true. Fluorine is more electronegative than chlorine, so it has a higher tendency to gain electrons (oxidize other substances) compared to chlorine. Therefore, fluorine is a stronger oxidizing agent than chlorine.

B. Sulfur in the vapor state shows paramagnetic behavior.

This statement is true. In the vapor state, sulfur ($S_8$) exists as $S_2$ molecules. Each $S_2$ molecule has two unpaired electrons, making sulfur paramagnetic.

C. $H_2S$ is more acidic than $H_2Te$

This statement is false. Acidity increases down a group in the periodic table. Since tellurium ($Te$) is below sulfur ($S$) in the same group (Group 16 or Group VI-A), $H_2Te$ is expected to be more acidic than $H_2S$.

D. Fluorine forms two oxoacids $HOF$ and $HOFO$.

This statement is false. Fluorine does not form oxoacids. It primarily forms hydrofluoric acid ($HF$), which is not an oxoacid.

So, the correct choice is: 1. A and B only