CUET Preparation Today
The value of $\frac{2 tan 60°}{1+tan^2 60°}$ is: |
cos 60° tan 60° sin 60° sin 30° |
sin 60° |
tan60° = $\sqrt{3}$ $\frac{2 tan 60°}{1+tan^2 60°}$ = $\frac{2 \sqrt{3}}{1+(\sqrt{3})^2}$ = $\frac{2 \sqrt{3}}{4}$ = $\frac{ \sqrt{3}}{2}$ = sin60° |
