The value of $\frac{2 tan 60°}{1+tan^2 60°}$ is:
Answer & explanation
Correct answer: option 3
tan60° = $\sqrt{3}$
$\frac{2 tan 60°}{1+tan^2 60°}$
= $\frac{2 \sqrt{3}}{1+(\sqrt{3})^2}$
= $\frac{2 \sqrt{3}}{4}$
= $\frac{ \sqrt{3}}{2}$
= sin60°
The value of $\frac{2 tan 60°}{1+tan^2 60°}$ is:
Correct answer: option 3
tan60° = $\sqrt{3}$
$\frac{2 tan 60°}{1+tan^2 60°}$
= $\frac{2 \sqrt{3}}{1+(\sqrt{3})^2}$
= $\frac{2 \sqrt{3}}{4}$
= $\frac{ \sqrt{3}}{2}$
= sin60°