A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C finishes it in 13 days. In how many days B alone could finish the work?
Answer & explanation
Correct answer: option 1
Let total work = 48
(A + B) : (B + C)
12 : 16 Days
4 : 3 Efficiency
Here,
Say, A works for 5 and B works for 5 days with A and
B works for 2 more days with C.
So,
⇒ Work done by (A + B) in 5 days = 5 x 4 = 20
⇒ Work done by (B + C) in 2 days = 2 x 3 = 6
Remaining work done by C in 11 days = 48 - 26 = 22
⇒ Efficiency of C = 2, similarly B = 1, A = 3
B alone finishes the work in \(\frac{48}{1}\) = 48 days