CUET Preparation Today
A coin is tossed 6 times. The probability that tail appears odd number of times is : |
${^6C}_3\left(\frac{1}{2}\right)^6$ $\left(\frac{1}{2}\right)^6$ $\frac{1}{2}$ ${^6C}_4\left(\frac{1}{2}\right)^6$ |
$\frac{1}{2}$ |
The correct answer is Option (3) → $\frac{1}{2}$ The number of total possible outcome, $2^6=64$ Exactly 1 tail : ${^6C}_1=6$ Exactly 3 tail : ${^6C}_3=20$ Exactly 5 tail : ${^6C}_5=6$ ∴ Probability = $\frac{20+6+6}{64}=\frac{1}{2}$ |
