A coin is tossed 6 times. The probability that tail appears odd number of times is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{2}$
The number of total possible outcome,
$2^6=64$
Exactly 1 tail : ${^6C}_1=6$
Exactly 3 tail : ${^6C}_3=20$
Exactly 5 tail : ${^6C}_5=6$
∴ Probability = $\frac{20+6+6}{64}=\frac{1}{2}$