An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop?

15 km

The angle of tilt of the aircraft is given by,

tanθ= v²/rg

Here, θ is the angle of tilt of the aircraft, r is the radius of the loop, v is the loop speed and g is the acceleration due to gravity.

Substitute the values in the above equation.

\(r = \frac{720 \text{km/h}\frac{1}{3600} \text{s}}{10 \text{m} \frac{1}{1000} \text{km}} \) ≈ 15 Km

Thus, the radius of the loop is 15 km.