Practicing Success
The value of $tan^{-1}(tan(-6))$, is |
$2\pi - 6 $ $2\pi + 6 $ $ 6-2\pi $ $3\pi - 6 $ |
$2\pi - 6 $ |
We know that $tan^{-1} (tan \theta)= \theta $, if $-\frac{\pi}{2}< \theta < \frac{\pi}{2}$. Here, $ \theta = - 6$ radians which does not lie between $-\frac{\pi}{2}$ and $\frac{\pi}{2}$. However, $2\pi - 6 $ lies between $-\frac{\pi}{2}$ and $\frac{\pi}{2}$ such that $tan (2\pi - 6 ) = - tan 6 = tan (-6)$ $∴ tan^{-1}[tan (-6)]= tan^{-1} [tan (2\pi - 6)] = 2 \pi - 6 $ |