Practicing Success
If $sinθ=\frac{\sqrt{3}}{2}$, and θ is an acute angle, find the value of cos3θ ? |
$\frac{1}{2}$ 1 -1 0 |
-1 |
sinθ = \(\frac{ √3}{2}\) { we know, sin30º = \(\frac{ √3}{2}\) } So, θ = 30º Now, cos 3θ = cos (3 × 30º) = cos 90º = 1 { We know, cos 90º = 1 } |