Practicing Success
A particle A of mass m and charge Q moves directly towards a fixed particle B. Which has charge Q. The speed of A is v when it is far away from B. The minimum separation between the particle is proportional to |
v v2 v-1 v-2 |
v-2 |
From Conservation of energy (KE + EPE)minimum separation = (KE + EPE)far away $\Rightarrow 0+\frac{1}{4 \pi \varepsilon_{\circ}} \frac{Q^2}{r_{\min }}=\frac{1}{2} m v^2+0$ $\Rightarrow r_{\min } \propto \frac{1}{v^2}$ Hence, (D) is correct choice. |