A particle A of mass m and charge Q moves directly towards a fixed particle B. Which has charge Q. The speed of A is v when it is far away from B. The minimum separation between the particle is proportional to
Answer & explanation
Correct answer: option 4
From Conservation of energy
(KE + EPE)minimum separation = (KE + EPE)far away
$\Rightarrow 0+\frac{1}{4 \pi \varepsilon_{\circ}} \frac{Q^2}{r_{\min }}=\frac{1}{2} m v^2+0$
$\Rightarrow r_{\min } \propto \frac{1}{v^2}$
Hence, (D) is correct choice.