A candidate scoring x% marks in an examination and fails by ‘a’ marks, while another candidate who scores y% marks gets ‘b’ marks more than the passing marks. Find the maximum marks of the examination.

\(\frac{100(a+b)}{(y-x)}\)

Let the maximum marks for the examination 'P'

\(\frac{(P+x)}{100}\) + 9 = \(\frac{(P+y)}{100}\) - b

a + b = \(\frac{P}{100}\) (y-x)

P = (\(\frac{a+b}{y-x}\)) x 100 = \(\frac{100(a+b)}{(y-x)}\)