If x2 - 32x + 1= 0
and x > 1, then the value of
x2 + \(\frac{1}{x^2}\) will be:
Answer & explanation
Correct answer: option 4
If x2 - 32x + 1= 0
Divide by x on both sides,
x + \(\frac{1}{x}\) = 32
x2 + \(\frac{1}{x^2}\) = 322 - 2 = 1022
If x + \(\frac{1}{x}\) = a
x2 + \(\frac{1}{x^2}\) = a2 - 2