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Evaluate $\Delta = \begin{vmatrix} 3 & 2 & 3 \\ 2 & 2 & 3 \\ 3 & 2 & 3 \end{vmatrix}$. |
3 2 0 18 |
0 |
The correct answer is Option (3) → 0 ## Expanding along first row, we get $\Delta = 3(6 - 6) - 2(6 - 9) + 3(4 - 6)$ $= 0 - 2(-3) + 3(-2) = 6 - 6 = 0$ |
