A metal ion from the first transition series has a magnetic moment (calculated) of 2.83 B.M. How many unpaired electrons are expected to present in the ion?
Answer & explanation
Correct answer: option 2
Magnetic moment is given by, u = \(\sqrt {n(n+2) }\)
If n = 2
u = \(\sqrt {2(2+2) }\) = \(\sqrt { 2 × 4}\) = \(\sqrt {8 }\) = 2.83 B.M.