A direct current of $5 A$ a superimposed on ac alternating current $I= 10 \sin ωt$ flowing through a wire The effective value of the resulting current will be

$5\sqrt{3} A$

$\text{ DC equivalent of current } I = 10 sin\omega t \text{ is } \frac{10}{\sqrt 2}$

$\text{Resultant of two currents are } I = \sqrt{5^2+ (5\sqrt 2)^2} = 5\sqrt 3 A$