CUET Preparation Today
CUET
Physics
Alternating Current
a
b
c
d
$\text{ DC equivalent of current } I = 10 sin\omega t \text{ is } \frac{10}{\sqrt 2}$
$\text{Resultant of two currents are } I = \sqrt{5^2+ (5\sqrt 2)^2} = 5\sqrt 3 A$
