Find the area of the region bounded by the curve $y^2 = 4x$, $y$-axis and line $y = 3$.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{9}{4}$
$\text{Required area} = \int_{0}^{3} \frac{y^2}{4} \, dy = \left[ \frac{y^3}{12} \right]_{0}^{3}$
$= \frac{27}{12} - 0 = \frac{9}{4} \text{ square units}$