Which two numbers, from amongst the given options, should be interchanged to make the given equation correct?
$(6)^2 - 20+(28 ÷7) - [\sqrt{4}×8] +(2)^2 = 40 $
Answer & explanation
Correct answer: option 1
Interchanging number;
--> Option 01= 06 and 08
So,
$(8)^2 - 20 + (28 ÷ 7) - [\sqrt{4} × 6] + (2)^2 = 40 $
64 - 20 + (4) - (2 x 6) + 4 = 40
44 + 4 - 12 + 4 = 40
48 - 12 + 4 = 40
36 + 4 = 40
Therefore, 40 = 40 (CORRECT)