Which two numbers, from amongst the given options, should be interchanged to make the given equation correct? $(6)^2 - 20+(28 ÷7) - [\sqrt{4}×8] +(2)^2 = 40 $

6 and 8   7 and 2 2 and 8  20 and 8

6 and 8

Interchanging number; --> Option 01= 06 and 08 So, $(8)^2 - 20 + (28 ÷ 7) - [\sqrt{4} × 6] + (2)^2 = 40 $ 64 - 20 + (4) - (2 x 6) + 4 = 40 44 + 4 - 12 + 4 = 40 48 - 12 + 4 = 40 36 + 4 = 40 Therefore, 40 = 40 (CORRECT)