Which two numbers, from amongst the given options, should be interchanged to make the given equation correct?

$(6)^2 - 20+(28 ÷7) - [\sqrt{4}×8] +(2)^2 = 40 $

6 and 8 

Interchanging number;

--> Option 01= 06 and 08

So,

$(8)^2 - 20 + (28 ÷ 7) - [\sqrt{4} × 6] + (2)^2 = 40 $

64 - 20 + (4) - (2 x 6) + 4 = 40

44 + 4 - 12 + 4 = 40

48 - 12 + 4 = 40

36 + 4 = 40

Therefore, 40 = 40 (CORRECT)