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If $\frac{a}{b} + \frac{b}{a} = 1$ and a + b = 2 , then the value of a3 + b3 is: |
0 3 1 2 |
0 |
If $\frac{a}{b} + \frac{b}{a} = 1$ \(\frac{a^2 + b^2}{ab}\) = 1 a2 + b2 = ab a3 + b3 = ( a + b ) ( a2 + b2 - ab ) a3 + b3 = 2 ( 1- 1 ) a3 + b3 = 0 |
