Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:
The solution of the differential equation \(\frac{dy}{dx}=e^{y+x}+e^{y-x}\) is
Options:
\(e^{-y}=e^{x}+e^{-x}+c\)
\(e^{-y}=e^{x}-e^{-x}+c\)
\(e^{-y}=e^{-x}-e^{x}+c\)
None of the above
Correct Answer:
\(e^{-y}=e^{-x}-e^{x}+c\)
Explanation:
\(\begin{aligned}\text{Given, }\frac{dy}{dx}&=e^{y}(e^{x}+e^{-x})\\ e^{-y}dy&=(e^{x}+e^{-x})dx\\ e^{-y}&=e^{-x}-e^{x}+c\end{aligned}\)