The solution of the differential equation \(\frac{dy}{dx}=e^{y+x}+e^{y-x}\) is
Answer & explanation
Correct answer: option 3
\(\begin{aligned}\text{Given, }\frac{dy}{dx}&=e^{y}(e^{x}+e^{-x})\\ e^{-y}dy&=(e^{x}+e^{-x})dx\\ e^{-y}&=e^{-x}-e^{x}+c\end{aligned}\)