A shopkeeper bought 95 dozen oranges at ₹4.50 each. 7 dozen oranges were rotten and so were discarded. He sold the remaining oranges at ₹78 per dozen. What is his profit or loss per cent (to the nearest integer)?
Answer & explanation
Correct answer: option 2
CP of 95 dozen oranges = 4.50 × 95 × 12 = 5130
Remaining oranges = 95 - 7 = 88 dozen
SP of 88 dozen oranges = 78 × 88 = 6864
Profit% = \(\frac{6864 - 5130}{5130}\) × 100
\(\frac{1734}{5130}\) × 100 = 34%