If sec θ - cos θ = 14 and 14sec θ = x, then the value of x is _________.

$tan^2θ$ $sec^2θ$ $2sec θ$ $2tan θ$

$tan^2θ$

sec θ - cos θ = 14 { we know, cos θ = \(\frac{1}{ secθ}\) } sec θ - \(\frac{1}{ secθ}\) = 14 sec²θ - 14 sec θ  - 1 = 0 { we know, sec²θ - tan²θ = 1 } tan²θ = 14 sec θ    -----(1) ATQ, 14 sec θ = x     ----(2) From 1 and 2 . x = tan²θ