If the lines $\frac{x - 2}{2k} = \frac{y - 3}{3} = \frac{z + 2}{-1}$ and $\frac{x - 2}{8} = \frac{y - 3}{6} = \frac{z + 2}{-2}$ are parallel, then find the value of $k$.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2 ##
Given lines are:
$\frac{x - 2}{2k} = \frac{y - 3}{3} = \frac{z + 2}{-1}$
and $\frac{x - 2}{8} = \frac{y - 3}{6} = \frac{z + 2}{-2}$
The direction ratios of the first line are $(2k, 3, -1)$ and the direction ratios of the second line are $(8, 6, -2)$.
Lines are parallel;
So, $\frac{2k}{8} = \frac{3}{6} = \frac{-1}{-2} \Rightarrow \frac{k}{4} = \frac{1}{2} = \frac{1}{2}$
$\Rightarrow k = 2$