\(E^o_{K^+/K} = -2.93V, \text{ } E^o_{Ag^+/Ag} =0.8V, \text{ }E^o_{Cu^{2+}/Cu} = 0.34V\)
\(E^o_{Ni^{2+}/Ni} = -0.25V, \text{ } E^o_{Li^+/Li} =-3.05V\)
Arrange the following metals in increasing order of their reducing power.
A. K
B. Ag
C. Cu
D. Ni
E. Li
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is option 3. B < C < D < A < E.
The reducing power of a metal is inversely proportional to its standard electrode potential. This means that the metal with the most negative standard electrode potential will have the highest reducing power.
Here is a table of the metals and their standard electrode potentials:
|
Metal |
Standard electrode potential (V) |
|
Li |
-3.05 |
|
K |
-2.93 |
|
Ni |
-0.25 |
|
Cu |
0.34 |
|
Ag |
0.80 |
Based on the table, we can arrange the metals in increasing order of reducing power as follows:
Li < K < Ni < Cu < Ag
Therefore, the correct answer is 4. B < C < A < E < D.