\(E^o_{K^+/K} = -2.93V, \text{ } E^o_{Ag^+/Ag} =0.8V, \text{ }E^o_{Cu^{2+}/Cu} = 0.34V\)

\(E^o_{Ni^{2+}/Ni} = -0.25V, \text{ } E^o_{Li^+/Li} =-3.05V\)

Arrange the following metals in increasing order of their reducing power.

A. K

B. Ag

C. Cu

D. Ni

E. Li

Choose the correct answer from the options given below:

B < C < D < A < E

The correct answer is option 3. B < C < D < A < E.

The reducing power of a metal is inversely proportional to its standard electrode potential. This means that the metal with the most negative standard electrode potential will have the highest reducing power.

Here is a table of the metals and their standard electrode potentials:

Based on the table, we can arrange the metals in increasing order of reducing power as follows:

Li < K < Ni < Cu < Ag

Therefore, the correct answer is 4. B < C < A < E < D.