If decreasing 110 by x% gives the same result increasing 50 by x%, then x% of 650 is what percentage more than (x+20)% of 180? (correct to nearest integer)

136%

According to question ,

110 × \(\frac{100-x}{100}\) = 50 × \(\frac{100+x}{100}\)

1100 - 11x = 500 + 5x

16x = 600

x = 37.5

x% of 650 =  \(\frac{37.5}{100}\) × 650

= 243.75

(x+20)% of 180 =  \(\frac{37.5+20}{100}\) × 180

= 103.5

Required Difference = 243.75 - 103.5 = 140.25

Required percentage = \(\frac{140.25}{103.5}\) × 100%  = 136% (approx.)