If decreasing 110 by x% gives the same result increasing 50 by x%, then x% of 650 is what percentage more than (x+20)% of 180? (correct to nearest integer)
Answer & explanation
Correct answer: option 1
According to question ,
110 × \(\frac{100-x}{100}\) = 50 × \(\frac{100+x}{100}\)
1100 - 11x = 500 + 5x
16x = 600
x = 37.5
x% of 650 = \(\frac{37.5}{100}\) × 650
= 243.75
(x+20)% of 180 = \(\frac{37.5+20}{100}\) × 180
= 103.5
Required Difference = 243.75 - 103.5 = 140.25
Required percentage = \(\frac{140.25}{103.5}\) × 100% = 136% (approx.)