Let $f:[-2, 2]→ [-2, 2]$ be a function defined by $f(x)= x|x|$, then f i s:

One-one but not onto Onto but not one-one Neither one-one nor onto Bijective

One-one but not onto

The correct answer is Option (1) → One-one but not onto $f(x)=x|x|=\left\{\begin{matrix}x^2,&x≥0\\-x^2,&x<0\end{matrix}\right.$ $f(x_1)=f(x_2)=x_1|x_1|=x_2|x_2|$ $⇒x_1=x_2$ (one one function) Not onto for x = 2 $f(x)=4$ which is not present in f is range Range ≠ codomain