Solve: $x(x-1) (x-2) (x-3) > 0$. |
$(−∞,0)∪(1,2)∪(3,∞)$ $(0,1)∪(2,3)$ $(−∞,0)∪(0,1)∪(1,2)∪(2,3)∪(3,∞)$ $(−∞,0)∩(1,2)∩(3,∞)$ |
$(−∞,0)∪(1,2)∪(3,∞)$ |
The correct answer is Option (1) → $(−∞,0)∪(1,2)∪(3,∞)$ Given $x(x-1) (x-2) (x-3) > 0$. Mark the numbers 0, 1, 2, 3 on real line. By method of intervals, we see that given inequality is satisfied when x > 3 or 1 < x < 2 or x < 0. ∴ The solution set is $(−∞,0)∪(1,2)∪(3,∞)$. |