Visible light of wavelength 600 nm falls normally on a single slit and diffraction pattern is obtained on a screen. It is found that the second diffraction minima is at $(π/3)$. If the first minimum is obtained at $θ_1$, then $θ_1$ is

Given: $\left(\sin 25° =\frac{\sqrt{3}}{4}\right)$

$(5π/36)$

The correct answer is Option (3) → $(5π/36)$