Practicing Success
Light of wavelength 6000 Å is normally incident on a slit. Angular position of second minimum from central maximum us 30°. Width of the slit should be |
$12 × 10^{–5} cm$ $18 × 10^{–5} cm$ $24× 10^{–5} cm$ $36× 10^{–5} cm$ |
$24× 10^{–5} cm$ |
$a\,\sin θ=nλ$ $a=\frac{nλ}{\sin θ}=\frac{2×6000×10^{-10}}{\sin 30°}$ $=\frac{2×6000×10^{-10}}{1/2}=4×6000×10^{-10}$ $2410^{-10}10^{-7}m=24× 10^{–5} cm$ |