Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Light of wavelength 6000 Å is normally incident on a slit. Angular position of second minimum from central maximum us 30°. Width of the slit should be

Options:

$12 × 10^{–5} cm$

$18 × 10^{–5} cm$

$24× 10^{–5} cm$

$36× 10^{–5} cm$

Correct Answer:

$24× 10^{–5} cm$

Explanation:

$a\,\sin θ=nλ$

$a=\frac{nλ}{\sin θ}=\frac{2×6000×10^{-10}}{\sin 30°}$

$=\frac{2×6000×10^{-10}}{1/2}=4×6000×10^{-10}$

$2410^{-10}10^{-7}m=24× 10^{–5} cm$