Practicing Success
A conducting 1 rod of mass ‘m’ and length ‘l’ is changed horizontally with the help of two insulating threads such that the rod is along east-west direction. Now current I is set up form west to east direction. What should be magnitude and direction of magnetic field. So that tension in the threads becomes zero? |
$B=\frac{mg}{Il}$, towards north $B=\frac{mg}{Il}$, towards south $B=\frac{mg}{Il}$, upwards $B=\frac{mg}{Il}$,downwards |
$B=\frac{mg}{Il}$, towards north |
The correct answer is option (1) : $B=\frac{mg}{Il}$, towards north $mg=B/L$ $B=\frac{mg}{IL},$ towards north to ensure that magnetic force upwards. |