The value of magnetic field between plates of capacitor, at distance of 1m from centre where electric field varies by 1010 V/m/s will be:
Answer & explanation
Correct answer: option 4
$ B = \frac{\mu_0 \epsilon_0 r}{2} \frac{dE}{dt} = \frac{1}{2\times 9\times 10^{16}} 10^{10}= 5.56\times 10^{-8} T = 55.6nT$