Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

If t(n) = Number of positive divisors of n, n ∈ N, then what is the value of $t(28)$?

Options:

4

6

8

7

Correct Answer:

6

Explanation:

The correct answer is option (2) : 6

$28= 1×28$

$28=2×14$

$28=4×7$

So, +ve divisions of $28=1,2, 4, 7, 14,28$

$∴t(28)= 6$