If sin (3α - 45°) = cos (45° - 2α) then the value of sinα + cos\(\frac{a}{2}\) + tan\(\frac{2a}{3}\) .
Answer & explanation
Correct answer: option 4
[Concept: sin A = cos B, when A + B = 90°]
Therefore,
(3a - 45° + 45° - 2α) = 90°
α = 90°
Put this value in find →
⇒ sinα + cos \(\frac{a}{2}\) + tan \(\frac{2a}{3}\)
⇒ sin90° + cos45° + tan60°
= 1 + \(\frac{1}{\sqrt {2}}\) + \(\sqrt { 3}\)
= \(\frac{√2 + 1 + √6 }{\sqrt {2}}\)