Find the area of a triangle whose length of each side is 13 inches, 15 inches and 14 inches.
Answer & explanation
Correct answer: option 1
Length of each side is 13 inches, 15 inches and 14 inches.
The area of the triangle = \(\sqrt {s(s-a)(s-b)(s-c) }\)
s = \(\frac{a + b + c}{2}\) = \(\frac{13 + 14 + 15}{2}\) = 21
The area of the triangle = \(\sqrt {21(21-13)(21-14)(21-15)}\)
= \(\sqrt {21(8)(7)(6)}\)
= 84 cm2