Find the area of a triangle whose length of each side is 13 inches, 15 inches and 14 inches.

84 square inches

Length of each side is 13 inches, 15 inches and 14 inches.

The area of the triangle = \(\sqrt {s(s-a)(s-b)(s-c) }\)

s = \(\frac{a + b + c}{2}\) = \(\frac{13 + 14 + 15}{2}\) = 21

The area of the triangle = \(\sqrt {21(21-13)(21-14)(21-15)}\)

                                  =  \(\sqrt {21(8)(7)(6)}\)

                                  = 84 cm²