Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

Let charge per unit area is $\sigma = \frac{Q}{4\pi R^2}$

Electric Field due to sphere near its surface$ E = \frac{\sigma}{2\epsilon_0}$

Force on its unit area $ F = \sigma \times E = \sigma \times \frac{\sigma}{2\epsilon_0}= \frac{\sigma^2}{2\epsilon_0} = 515.7 N/m^2$