Practicing Success
The ratio of speed of an electron in ground state in Bohr's first orbit of hydrogen atom to velocity of light in air is |
$\frac{e^2}{2 \varepsilon_0 h c}$ $\frac{2 e^2 \varepsilon_0}{h c}$ $\frac{e^3}{2 \varepsilon_0 h c}$ $\frac{2 \varepsilon_0 h c}{e^2}$ |
$\frac{e^2}{2 \varepsilon_0 h c}$ |
Speed of electron in nth orbit (in CGS) $v_n=\frac{2 \pi Z e^2}{n h}(k=1)$ For first orbit H2 ; n = 1 and Z = 1 So $v=\frac{2 \pi e^2}{h} \Rightarrow \frac{v}{c}=\frac{2 \pi e^2}{h c}$ |