The ratio of speed of an electron in ground state in Bohr's first orbit of hydrogen atom to velocity of light in air is
Answer & explanation
Correct answer: option 1
Speed of electron in nth orbit (in CGS) $v_n=\frac{2 \pi Z e^2}{n h}(k=1)$
For first orbit H2 ; n = 1 and Z = 1
So $v=\frac{2 \pi e^2}{h} \Rightarrow \frac{v}{c}=\frac{2 \pi e^2}{h c}$