Target Exam

CUET

Subject

Section B1

Chapter

Differential Equations

Question:

The general solution of the differential equation $ydx - xdy = 0$; (Given $x, y > 0$), is of the form:

(Where '$c$' is an arbitrary positive constant of integration)

Options:

$xy = c$

$x = cy^2$

$y = cx$

$y = cx^2$

Correct Answer:

$y = cx$

Explanation:

The correct answer is Option (3) → $y = cx$ ##

The given differential equation is:

$ydx - xdy = 0$

Rewrite the differential equation:

$\frac{dx}{x} = \frac{dy}{y}$

Integrating both sides:

$\int \frac{dx}{x} = \int \frac{dy}{y}$

$\log y = \log x + \log c$

$y = cx$