Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

In an experiment, a student in the laboratory measures the terminal potential difference (V) of a cell (emf E and internal resistance r) as a function of current I flowing through it and plot a graph taking V on y-axis and I on x-axis. What is the slope of the graph between V and I?

Options:

$r^2$

$-r^2$

$r$

$-r$

Correct Answer:

$-r$

Explanation:

The correct answer is Option (4) → $-r$

The terminal potential difference (v) of a cell is related to its emf (E), current (I), and internal resistance (r) by -

$V=E-Ir$ [By Ohm's law]

This is a linear equation of the form

$V=-Ir+E$ [$y=mx+c$]

where,

$-r$ is the slope.