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-- Mathematics - Section B1
Relations and Functions
If f: Z → Z, f = x + 2 and g: Z → Z with gof = Iz, then g is
x + 2
x – 2
x – 1
x + 1
gof = Iz ⇒ (gof)(x) = x for all x ∈ Z so that g(f(x)) = x
or g(x + 2) = x ⇒ g(x) = x - 2, x ∈ Z.
Hence (B) is the correct answer.