The following table shows the income(in rupees) for a particular month, together with their source, in respect of 5 employees (A, B, C, D and E).
|
Employee |
A |
B |
C |
D |
E |
|
Salary |
52,000 |
48,500 |
42,000 |
31,000 |
25,000 |
|
Overtime |
0 |
0 |
1,500 |
2,500 |
3,200 |
|
Arrears |
5,500 |
4,500 |
4,000 |
3,000 |
1,500 |
|
Bonus |
3,500 |
3,000 |
2,500 |
2,000 |
2,000 |
|
Miscellaneous income |
5,000 |
3,000 |
2,000 |
1,500 |
0 |
|
Total |
66,000 |
59,000 |
52,000 |
40,000 |
31,700 |
How many employees got more arrears than the average arrears received by all the employees?
Answer & explanation
Correct answer: option 3
Average arrears received by all = \(\frac{5500 + 4500 + 4000 + 3000 + 1500}{5}\)
= \(\frac{ 18500}{5}\)
= 3700
Arrears of A , B & C is more than 3700 i.e. 5500 , 4500 & 400 respectively.
Ans :- 3