A straight conductor of length 0.4 m is moved with a speed of 7 m-1 perpendicular to a magnetic field of induction 0.9 Wb/m2 and the length of the conductor. The induced e.m.f. across the conductor is: (a) 25.2 V (b) 5.04 V (c) 2.52 V (d) 1.26 V |
a b c d |
c |
The induced emf (ε) in a conductor moving in a magnetic field is - $ε=B.l.v$ [Faraday's Law] where, B, Magnetic field = 0.9 T $l$, length of conductor = 0.4 m v, velocity of conductor = 7 m/s $ε=0.9×0.4×7$ $=2.52V$ |