Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

A straight conductor of length 0.4 m is moved with a speed of 7 m-1 perpendicular to a magnetic field of induction 0.9 Wb/m2 and the length of the conductor. The induced e.m.f. across the conductor is:

(a) 25.2 V

(b) 5.04 V

(c) 2.52 V

(d) 1.26 V

Options:

a

b

c

d

Correct Answer:

c

Explanation:

The induced emf (ε) in a conductor moving in a magnetic field is -

$ε=B.l.v$ [Faraday's Law]

where,

B, Magnetic field = 0.9 T

$l$, length of conductor = 0.4 m

v, velocity of conductor = 7 m/s

$ε=0.9×0.4×7$

$=2.52V$