Practicing Success
Practicing Success
CUET Preparation Today
If A, B are square matrices of order 3, A is non-singular and $AB=O$, then B is a |
null matrix singular matrix unit matrix non-singular matrix |
null matrix |
It is given that $|A| ≠ 0$. So, $A^{-1}$ exists. Now, $AB=O$ $⇒A^{-1} (AB) = A^{-1}O$ $⇒(A^{-1}A) B=O⇒ IB=O ⇒ B=O$ |
