If A, B are square matrices of order 3, A is non-singular and $AB=O$, then B is a
Answer & explanation
Correct answer: option 1
It is given that $|A| ≠ 0$. So, $A^{-1}$ exists.
Now,
$AB=O$
$⇒A^{-1} (AB) = A^{-1}O$
$⇒(A^{-1}A) B=O⇒ IB=O ⇒ B=O$
If A, B are square matrices of order 3, A is non-singular and $AB=O$, then B is a
Correct answer: option 1
It is given that $|A| ≠ 0$. So, $A^{-1}$ exists.
Now,
$AB=O$
$⇒A^{-1} (AB) = A^{-1}O$
$⇒(A^{-1}A) B=O⇒ IB=O ⇒ B=O$