A compound microscope has an objective lens of focal length fo = 1.0 cm, an eyepiece of focal length 2.2 cm and has tube length 22 cm. The magnification produced compound microscope is

–250 –200 –100 –150

–250

The correct answer is Option (1) → –250 $M.P=\frac{L}{f_o} \frac{D}{f_e}$ $=-\frac{22 \times 25}{1 \times 2.2}$ M.P = -250