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Which state of triply ionised Baryllium (Be+++) has the same orbital radius as that of the ground state of hydrogen |
n = 4 n = 3 n = 2 n = 1 |
n = 2 |
Radius of nth orbit for any hydrogen like atom $r_n=r_0\left(\frac{n^2}{Z}\right)$ ($r_0$ radius of first orbit of H2 - atom) If $r_n=r_0 \Rightarrow n=\sqrt{Z}$. For $B e^{++1}, Z=4 \Rightarrow n = 2$ |
