If $(4a +\frac{5}{a} +5) = 14$, what is the value of $(16a^2 +\frac{25}{a^2})$ ?
Answer & explanation
Correct answer: option 3
If $(4a +\frac{5}{a} +5) = 14$
4a + \(\frac{5}{a}\) = 14 - 5 = 9
Put a = 1 that will satisfy the equation
$(16a^2 +\frac{25}{a^2})$ = $(16 × 1^2 +\frac{25}{1^2})$ = 16 + 25= 41