Practicing Success
Practicing Success
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If $(4a +\frac{5}{a} +5) = 14$, what is the value of $(16a^2 +\frac{25}{a^2})$ ? |
25 36 41 40 |
41 |
If $(4a +\frac{5}{a} +5) = 14$ 4a + \(\frac{5}{a}\) = 14 - 5 = 9 Put a = 1 that will satisfy the equation $(16a^2 +\frac{25}{a^2})$ = $(16 × 1^2 +\frac{25}{1^2})$ = 16 + 25= 41 |
