If \(x\) is real, the minimum value of \(x^2 - 8x + 20\) is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 4
Completing the square:
\(x^2 - 8x + 20 = (x^2 - 8x + 16) + 4\)
\( = (x - 4)^2 + 4\)
Since \((x - 4)^2 \ge 0\), with equality at x = 4, the minimum value is 4.