The value of the integral $\int\limits_0^{0.9}[x-2[x]] d x$, where [.] denotes the greatest integer function, is
Answer & explanation
Correct answer: option 2
$\int\limits_0^{0.9}[x-2[x]] d x$
$=\int\limits_0^{0.9}[x-2 \times 0] d x=\int\limits_0^{0.9}[x] d x=\int\limits_0^{0.9} 0 d x=0$