Find the integral \( \int \frac{ 1}{ x} dx\)1\[\frac{1}{ { x }^{ 2 } } + c\]2\[\frac{1}{ { x }^{ -2 } } + c\]3x + c4log x + cAnswer & explanation+Correct answer: option 4\( \int \frac{ 1}{ x} dx\) = log x +c
