The given table represents the number of engineers recruited by four companies A, B, C and D over the years. Study the table carefully and answer the question that follows.
|
Company → Year ↓ |
A
|
B
|
C
|
D
|
|
2014 |
120 |
90 |
85 |
105 |
|
2015 |
132 |
118 |
93 |
97 |
|
2016 |
128 |
98 |
94 |
100 |
|
2017 |
140 |
106 |
98 |
116 |
|
2018 |
148 |
112 |
105 |
125 |
|
2019 |
150 |
118 |
110 |
122 |
The number of the years in which the number of engineers recruited by company D is less than the average number of engineers recruited by B in the given six years, is:
Answer & explanation
Correct answer: option 1
Average number of engineers recruited in B = \(\frac{90 + 118 + 98 + 106 + 112 + 118 }{6}\)
= \(\frac{642 }{6}\)
= 107
Number of engineers recruited in D in 2014 , 2015 & 2016 is 105 , 97 & 100 which is less than 107.
Ans :- 3