The bar graph given below shows the number of players participating in two games in six different schools L, M, N, P, Q and R.

Total number of players participating in game D from all schools is what percentage of the total number of players participating in game E from all schools ?

75.3 percent

Total players in game D = 92 + 78 + 66 + 88 + 54 + 110 = 488

Total players in game E = 146 + 102 + 82 + 104 + 96 + 118 = 648

Required percentage = \(\frac{488}{648}\) × 100 = 75.3%