Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Match List-I with List-II

List-I

List-II

(A) $f(x) =|x| + 1$

(I) Not differentiable at $x = 3$ only

(B) $f(x)=|x -3|$

(II) Not differentiable at $x = -3$ only

(C) $f(x) =|x+3|$

(III) Not differentiable at $x = 3, -3$ only

(D) $f(x) =|x^2-9|$

(IV) Not differentiable at $x = 0$ only

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(III), (C)-(IV), (D)-(II)

(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Correct Answer:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Explanation:

The correct answer is Option (4) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

List-I

List-II

(A) $f(x) =|x| + 1$

(IV) Not differentiable at $x = 0$ only

(B) $f(x)=|x -3|$

(I) Not differentiable at $x = 3$ only

(C) $f(x) =|x+3|$

(II) Not differentiable at $x = -3$ only

(D) $f(x) =|x^2-9|$

(III) Not differentiable at $x = 3, -3$ only

(A) f(x) = |x| + 1
Here, the function is a vertical shift of |x|. Since |x| is not differentiable at x = 0 (it has a sharp corner there), this function is also not differentiable only at x = 0.
Match: (A) → (IV)

(B) f(x) = |x − 3|
This is a modulus function shifted right by 3 units. It has a corner (non-differentiability) at x = 3 only.
Match: (B) → (I)

(C) f(x) = |x + 3|
This is a modulus function shifted left by 3 units. So, it's not differentiable at x = −3 only.
Match: (C) → (II)

(D) f(x) = |x² − 9|
This expression becomes 0 when x² = 9 ⇒ x = ±3. So, modulus function is not differentiable at both x = 3 and x = −3.
Match: (D) → (III)