If Arun travels a certain distance at 8 km/h, he reaches his destination 12 min early. If he travels at a speed of 6 km/h, he reaches his destination 10 minutes late. Find the speed in (km/h) at which he should travel to reach his destination on time?

6\(\frac{10}{13}\)

Speed    →  8     :     6

time      →  6     :     8

                   ↓           ↓   (Diff. 2)  → = 22 (given)     

              6 × 11 =  66... (this time is 12 min earlier)

so actual time is = 66 + 12 = 78

S = \(\frac{D}{t}\)

D = s × t = \(\frac{8.8 × 60}{78 × 10}\) 

   = \(\frac{88}{13}\) = 6\(\frac{10}{13}\)